$(\dfrac{-9}{8})\times(\dfrac{-2}{5})$=

$(\dfrac{-4}{3}) : (\dfrac{-5}{4})$=

$(\dfrac{-5}{8})+\dfrac{5}{4}$=

$\dfrac{(\dfrac{-3}{2})}{\dfrac{2}{9}}$=

$\dfrac{\dfrac{8}{5}}{\dfrac{3}{2}}$=

$\dfrac{(\dfrac{-2}{3})}{\dfrac{5}{6}}$=

$\dfrac{9}{5}-\dfrac{4}{7}$=

$(\dfrac{-4}{5})\times\dfrac{5}{3}$=

$(\dfrac{-8}{7})+(\dfrac{-1}{2})$=

$\dfrac{\dfrac{5}{8}}{(\dfrac{-7}{5})}$=