$\dfrac{\dfrac{4}{7}}{(\dfrac{-2}{3})}$=

$\dfrac{(\dfrac{-2}{3})}{\dfrac{7}{8}}$=

$\dfrac{8}{7}-(\dfrac{-5}{9})$=

$\dfrac{\dfrac{5}{4}}{(\dfrac{-7}{9})}$=

$\dfrac{2}{9}\times(\dfrac{-3}{2})$=

$(\dfrac{-1}{2})+\dfrac{7}{9}$=

$\dfrac{7}{3} : (\dfrac{-9}{5})$=

$(\dfrac{-5}{7})\times\dfrac{8}{3}$=

$(\dfrac{-4}{3}) : \dfrac{8}{5}$=

$(\dfrac{-8}{5}) : \dfrac{6}{5}$=