$\dfrac{\dfrac{1}{2}}{(\dfrac{-3}{5})}$=

$\dfrac{9}{8}\times\dfrac{2}{9}$=

$\dfrac{(\dfrac{-3}{4})}{\dfrac{3}{2}}$=

$\dfrac{9}{5}\times(\dfrac{-3}{5})$=

$\dfrac{3}{7}\times\dfrac{7}{9}$=

$\dfrac{\dfrac{1}{2}}{\dfrac{7}{3}}$=

$(\dfrac{-7}{6})+\dfrac{2}{7}$=

$(\dfrac{-3}{8})-(\dfrac{-4}{5})$=

$(\dfrac{-4}{5})+(\dfrac{-7}{4})$=

$(\dfrac{-5}{9})\times(\dfrac{-3}{2})$=