$\dfrac{(\dfrac{-7}{9})}{(\dfrac{-1}{3})}$=

$\dfrac{5}{7}+(\dfrac{-6}{7})$=

$(\dfrac{-3}{2})+\dfrac{6}{5}$=

$\dfrac{5}{6}-\dfrac{3}{8}$=

$(\dfrac{-3}{2})-\dfrac{1}{2}$=

$\dfrac{3}{8} : \dfrac{8}{3}$=

$\dfrac{4}{3}\times(\dfrac{-3}{4})$=

$\dfrac{5}{6}+\dfrac{7}{8}$=

$(\dfrac{-3}{8})-(\dfrac{-1}{2})$=

$(\dfrac{-8}{7}) : (\dfrac{-9}{5})$=