$\dfrac{\dfrac{3}{4}}{(\dfrac{-7}{8})}$=

$(\dfrac{-1}{3})+\dfrac{2}{3}$=

$\dfrac{\dfrac{1}{2}}{\dfrac{2}{3}}$=

$\dfrac{6}{5} : (\dfrac{-6}{5})$=

$(\dfrac{-1}{2}) : \dfrac{1}{3}$=

$(\dfrac{-7}{6})\times(\dfrac{-9}{8})$=

$\dfrac{3}{2} : \dfrac{4}{9}$=

$\dfrac{9}{8} : (\dfrac{-3}{4})$=

$\dfrac{9}{5} : \dfrac{2}{5}$=

$\dfrac{2}{5}\times\dfrac{7}{6}$=